What is the answer to x^2+2sqrt(2x)-6=0 ?

The answer to x^2+2sqrt(2x)-6=0 is x\approx 1.56791…

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x^2+2sqrt(2x)-6=0

x^{2} + 2 2 x - 6 = 0

x \approx 1.56791 \dots

Solution steps

x^{2} + 2 2 x - 6 = 0

Remove square roots

8 x = x^{4} - 12 x^{2} + 36

Solve

8 x = x^{4} - 12 x^{2} + 36 : x \approx 3.34229 \dots, x \approx 1.56791 \dots

x \approx 3.34229 \dots, x \approx 1.56791 \dots

Verify Solutions:

x \approx 3.34229 \dots

False

, x \approx 1.56791 \dots

True

The solution is

x \approx 1.56791 \dots

2 x - 1 + 2 = \frac{( 3 x )}{( x - 1 )}

x + 2 x + x + 4 = 4 x - 1

x, v = d \cdot \frac{( 2 e _{0} )}{x}

x, 3 x + y = a

x = 5

What is the answer to x^2+2sqrt(2x)-6=0 ?
The answer to x^2+2sqrt(2x)-6=0 is x\approx 1.56791…
Solve for x: x^2+2sqrt(2x)-6=0
The solution is x\approx 1.56791…