What is the answer to x^2+4x=sqrt(x^2+4x) ?

The answer to x^2+4x=sqrt(x^2+4x) is x=0,x=-4,x=-2+sqrt(5),x=-2-sqrt(5)

Solve for x: x^2+4x=sqrt(x^2+4x)

The solution is x=0,x=-4,x=-2+sqrt(5),x=-2-sqrt(5)

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x^{2} + 4 x = x^{2} + 4 x

x = 0, x = - 4, x = - 2 + 5, x = - 2 - 5

Decimal Notation

x = 0, x = - 4, x = 0.23606 \dots, x = - 4.23606 \dots

Solution steps

x^{2} + 4 x = x^{2} + 4 x

Square both sides:

x^{4} + 8 x^{3} + 16 x^{2} = x^{2} + 4 x

x^{4} + 8 x^{3} + 16 x^{2} = x^{2} + 4 x

Solve

x^{4} + 8 x^{3} + 16 x^{2} = x^{2} + 4 x : x = 0, x = - 4, x = - 2 + 5, x = - 2 - 5

x = 0, x = - 4, x = - 2 + 5, x = - 2 - 5

Verify Solutions:

x = 0

True

, x = - 4

True

, x = - 2 + 5

True

, x = - 2 - 5

True

The solutions are

x = 0, x = - 4, x = - 2 + 5, x = - 2 - 5

2 x - 3 + 2 x + 4 = 6 x + 13

x^{0.4} = 8

3 x - 5 = x - 1

5 x^{\frac{1}{2}} = 2 x + 2

x + 5 - 2 x - 7 = 2

What is the answer to x^2+4x=sqrt(x^2+4x) ?
The answer to x^2+4x=sqrt(x^2+4x) is x=0,x=-4,x=-2+sqrt(5),x=-2-sqrt(5)
Solve for x: x^2+4x=sqrt(x^2+4x)
The solution is x=0,x=-4,x=-2+sqrt(5),x=-2-sqrt(5)