What is the answer to sqrt(x+5)-sqrt(2x-7)=2 ?

The answer to sqrt(x+5)-sqrt(2x-7)=2 is x=4

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sqrt(x+5)-sqrt(2x-7)=2

x + 5 - 2 x - 7 = 2

x = 4

Solution steps

x + 5 - 2 x - 7 = 2

Remove square roots

x^{2} - 16 x + 64 = 32 x - 112

Solve

x^{2} - 16 x + 64 = 32 x - 112 : x = 44, x = 4

x = 44, x = 4

Verify Solutions:

x = 44

False

, x = 4

True

The solution is

x = 4

3 x^{2} + 3 x - 2 + 2 x^{2} + 2 x - 3 = x^{2} + x + 1

x, x^{\frac{2}{3}} + y^{\frac{2}{3}} = a^{\frac{2}{3}}

x + 2 = 2 x + 1

x - 1 - 2 x + 1 = 0

(x - 2)^{\frac{2}{3}} + (x - 2)^{\frac{1}{3}} - 2 = 0

What is the answer to sqrt(x+5)-sqrt(2x-7)=2 ?
The answer to sqrt(x+5)-sqrt(2x-7)=2 is x=4
Solve for x: sqrt(x+5)-sqrt(2x-7)=2
The solution is x=4