What is the answer to m=sqrt(x^2+25) ?

The answer to m=sqrt(x^2+25) is x=sqrt(m^2-25) {m>= 5},x=-sqrt(m^2-25) {m>= 5}

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m=sqrt(x^2+25)

m = x^{2} + 25

x = m^{2} - 25 {m \geq 5}, x = - m^{2} - 25 {m \geq 5}

Solution steps

m = x^{2} + 25

Square both sides:

m^{2} = x^{2} + 25

m^{2} = x^{2} + 25

Solve

m^{2} = x^{2} + 25 : x = m^{2} - 25, x = - m^{2} - 25

x = m^{2} - 25, x = - m^{2} - 25

Verify Solutions:

x = m^{2} - 25 {m \geq 5}, x = - m^{2} - 25 {m \geq 5}

The solutions are

x = m^{2} - 25 {m \geq 5}, x = - m^{2} - 25 {m \geq 5}

\frac{( - 3 y - 4 2 y )}{2 \cdot y} = 0

2 x - 1 + 1 = x (3 - x)

3 x + 1 - 1 = 2 - x

4 x^{2} = x + 1

x + 1 = 9 x - 2

What is the answer to m=sqrt(x^2+25) ?
The answer to m=sqrt(x^2+25) is x=sqrt(m^2-25) {m>= 5},x=-sqrt(m^2-25) {m>= 5}