What are the solutions to the equation 3x^2-5x+6=0 ?

The solutions to the equation 3x^2-5x+6=0 are x= 5/6+i(sqrt(47))/6 ,x= 5/6-i(sqrt(47))/6

Find the zeros of 3x^2-5x+6=0

The zeros of 3x^2-5x+6=0 are x= 5/6+i(sqrt(47))/6 ,x= 5/6-i(sqrt(47))/6

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3 x^{2} - 5 x + 6 = 0

x = \frac{5}{6} + i \frac{47}{6}, x = \frac{5}{6} - i \frac{47}{6}

Solution steps

3 x^{2} - 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

Simplify

(- 5)^{2} - 4 \cdot 3 \cdot 6 : 47 i

x_{1, 2} = \frac{- ( - 5 ) \pm 47 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 47 i}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 47 i}{2 \cdot 3}

x = \frac{- ( - 5 ) + 47 i}{2 \cdot 3} : \frac{5}{6} + i \frac{47}{6}

x = \frac{- ( - 5 ) - 47 i}{2 \cdot 3} : \frac{5}{6} - i \frac{47}{6}

The solutions to the quadratic equation are:

x = \frac{5}{6} + i \frac{47}{6}, x = \frac{5}{6} - i \frac{47}{6}

(\frac{5}{9})^{- 1}

(x - 4)^{2} = 28

9 \cdot 13

- 3 x + 3 = 6

5 ∣ 2 x - 3 ∣ - 1 > 9

What are the solutions to the equation 3x^2-5x+6=0 ?
The solutions to the equation 3x^2-5x+6=0 are x= 5/6+i(sqrt(47))/6 ,x= 5/6-i(sqrt(47))/6
Find the zeros of 3x^2-5x+6=0
The zeros of 3x^2-5x+6=0 are x= 5/6+i(sqrt(47))/6 ,x= 5/6-i(sqrt(47))/6