What is the answer to solvefor x,20g*sqrt(x^3-9^2)=2 ?

The answer to solvefor x,20g*sqrt(x^3-9^2)=2 is x=\sqrt[3]{1/(100g^2)+81} {g 0}

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solvefor x,20g*sqrt(x^3-9^2)=2

solve for

x, 20 g \cdot x^{3} - 9^{2} = 2

Solution steps

20 g x^{3} - 9^{2} = 2

Divide both sides by

20 g

x^{3} - 9^{2} = \frac{1}{10 g}

Square both sides:

x^{3} - 81 = \frac{1}{100 g ^{2}}

x^{3} - 81 = \frac{1}{100 g ^{2}}

Solve

Verify Solutions:

The solution is

x - 2 = - 2 x + 14

9 x^{2} - 6 x + 1 = x + 2

5 x^{2} + 8 x + 10 = x^{4} + 4

[1.38 (8 + x)^{\frac{1}{2}}] - 1 = 0

2 + 4 x = - 1

What is the answer to solvefor x,20g*sqrt(x^3-9^2)=2 ?
The answer to solvefor x,20g*sqrt(x^3-9^2)=2 is x=\sqrt[3]{1/(100g^2)+81} {g<0\lor g>0}