What is the answer to sqrt(2x^2+3x+5)=x+3 ?

The answer to sqrt(2x^2+3x+5)=x+3 is x=4,x=-1

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sqrt(2x^2+3x+5)=x+3

2 x^{2} + 3 x + 5 = x + 3

x = 4, x = - 1

Solution steps

2 x^{2} + 3 x + 5 = x + 3

Square both sides:

2 x^{2} + 3 x + 5 = x^{2} + 6 x + 9

2 x^{2} + 3 x + 5 = x^{2} + 6 x + 9

Solve

2 x^{2} + 3 x + 5 = x^{2} + 6 x + 9 : x = 4, x = - 1

x = 4, x = - 1

Verify Solutions:

x = 4

True

, x = - 1

True

The solutions are

x = 4, x = - 1

x - 9 = 4 x + 9

x + 201 - x + 25 = 8

(4 x)^{\frac{1}{3}} - x = 0

x \cdot - 2 x^{2} + 6 x + 1 = - 4 x^{2} + 6 x + 1

a^{\frac{1}{2}} = 5

What is the answer to sqrt(2x^2+3x+5)=x+3 ?
The answer to sqrt(2x^2+3x+5)=x+3 is x=4,x=-1
Solve for x: sqrt(2x^2+3x+5)=x+3
The solution is x=4,x=-1