What is the answer to (4x)^{1/3}-x=0 ?

The answer to (4x)^{1/3}-x=0 is x=0,x=-2,x=2

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(4x)^{1/3}-x=0

(4 x)^{\frac{1}{3}} - x = 0

x = 0, x = - 2, x = 2

Solution steps

(4 x)^{\frac{1}{3}} - x = 0

Remove roots

4 x = x^{3}

Solve

4 x = x^{3} : x = 0, x = - 2, x = 2

x = 0, x = - 2, x = 2

Verify Solutions:

x = 0

True

, x = - 2

True

, x = 2

True

The solutions are

x = 0, x = - 2, x = 2

x \cdot - 2 x^{2} + 6 x + 1 = - 4 x^{2} + 6 x + 1

a^{\frac{1}{2}} = 5

x = 9

x^{2} + 4 x^{2} - 21 = 0

3 x + 1 - 2 x - 1 = 1

What is the answer to (4x)^{1/3}-x=0 ?
The answer to (4x)^{1/3}-x=0 is x=0,x=-2,x=2
Solve for x: (4x)^{1/3}-x=0
The solution is x=0,x=-2,x=2