What are the solutions to the equation v^2+7=8v ?

The solutions to the equation v^2+7=8v are v=7,v=1

Find the zeros of v^2+7=8v

The zeros of v^2+7=8v are v=7,v=1

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v^{2} + 7 = 8 v

v = 7, v = 1

Solution steps

v^{2} + 7 = 8 v

Move

8 v

to the left side

v^{2} + 7 - 8 v = 0

Write in the standard form

a x^{2} + b x + c = 0

v^{2} - 8 v + 7 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 7 = 6

v_{1, 2} = \frac{- ( - 8 ) \pm 6}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 8 ) + 6}{2 \cdot 1}, v_{2} = \frac{- ( - 8 ) - 6}{2 \cdot 1}

v = \frac{- ( - 8 ) + 6}{2 \cdot 1} : 7

v = \frac{- ( - 8 ) - 6}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

v = 7, v = 1

5 n^{2} + 9 n - 69 = 11

\frac{2 x}{4} = \frac{1 + x}{6}

5 p^{2} + 13 p - 6

\frac{5 - ( - 6 )}{- 4 - ( - 9 )}

\frac{2}{5} + \frac{3}{7}

What are the solutions to the equation v^2+7=8v ?
The solutions to the equation v^2+7=8v are v=7,v=1
Find the zeros of v^2+7=8v
The zeros of v^2+7=8v are v=7,v=1