What is the answer to solvefor x,sqrt(x)+sqrt(y)=4 ?

The answer to solvefor x,sqrt(x)+sqrt(y)=4 is x=16-8sqrt(y)+y

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solvefor x,sqrt(x)+sqrt(y)=4

solve for

x, x + y = 4

x = 16 - 8 y + y

Solution steps

x + y = 4

Move

y

to the right side

x = 4 - y

Square both sides:

x = 16 - 8 y + y

x = 16 - 8 y + y

Verify Solutions:

x = 16 - 8 y + y

True

The solution is

x = 16 - 8 y + y

\frac{4}{( x )} = 3 + x

5 x^{2} - 3 3 x - 6 = 0

\frac{6}{( x - 1 ) - 2 x - 1} = 1

\frac{2}{( 2 x + 1 ) + 1} = x

(1 + x)^{\frac{1}{3}} + (1 - x)^{\frac{1}{3}} = 2^{\frac{1}{3}}

What is the answer to solvefor x,sqrt(x)+sqrt(y)=4 ?
The answer to solvefor x,sqrt(x)+sqrt(y)=4 is x=16-8sqrt(y)+y