What is the answer to (1+x)^{1/3}+(1-x)^{1/3}=2^{1/3} ?

The answer to (1+x)^{1/3}+(1-x)^{1/3}=2^{1/3} is x=1,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1+x)^{1/3}+(1-x)^{1/3}=2^{1/3}

(1 + x)^{\frac{1}{3}} + (1 - x)^{\frac{1}{3}} = 2^{\frac{1}{3}}

x = 1, x = - 1

Solution steps

(1 + x)^{\frac{1}{3}} + (1 - x)^{\frac{1}{3}} = 2^{\frac{1}{3}}

Rewrite the equation with

(1 + x)^{\frac{1}{3}} = u

and

x = u^{3} - 1

u + (1 - (u^{3} - 1))^{\frac{1}{3}} = 2^{\frac{1}{3}}

Solve

u + (1 - (u^{3} - 1))^{\frac{1}{3}} = 2^{\frac{1}{3}} : u = 2^{\frac{1}{3}}, u = 0

u = 2^{\frac{1}{3}}, u = 0

Substitute back

u = (1 + x)^{\frac{1}{3}},

solve for

x

Solve

(1 + x)^{\frac{1}{3}} = 2^{\frac{1}{3}} : x = 1

Solve

(1 + x)^{\frac{1}{3}} = 0 : x = - 1

x = 1, x = - 1

Verify Solutions:

x = 1

True

, x = - 1

True

The solutions are

x = 1, x = - 1

d, b = r - r^{2} - d^{2}

[1.38 (64 + x^{2})^{\frac{1}{2}}] - 1 = 0

4 + 2 x - 4 = x

x + 7 x + 52 = 0

484 \cdot \frac{25}{x} = 22

What is the answer to (1+x)^{1/3}+(1-x)^{1/3}=2^{1/3} ?
The answer to (1+x)^{1/3}+(1-x)^{1/3}=2^{1/3} is x=1,x=-1
Solve for x: (1+x)^{1/3}+(1-x)^{1/3}=2^{1/3}
The solution is x=1,x=-1