What is the answer to solvefor x,z=xy+y*sqrt(x^2-a^2)+b ?

The answer to solvefor x,z=xy+y*sqrt(x^2-a^2)+b is x=(-a^2y^2+2bz-z^2-b^2)/(2y(b-z))

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solvefor x,z=xy+y*sqrt(x^2-a^2)+b

solve for

x, z = x y + y \cdot x^{2} - a^{2} + b

x = \frac{- a ^{2} y ^{2} + 2 b z - z ^{2} - b ^{2}}{2 y ( b - z )}

Solution steps

z = x y + y x^{2} - a^{2} + b

Remove square roots

- 2 b z - 2 x zy + z^{2} + b^{2} + x^{2} y^{2} + 2 b x y = x^{2} y^{2} - a^{2} y^{2}

Solve

- 2 b z - 2 x zy + z^{2} + b^{2} + x^{2} y^{2} + 2 b x y = x^{2} y^{2} - a^{2} y^{2} : x = \frac{- a ^{2} y ^{2} + 2 b z - z ^{2} - b ^{2}}{2 y ( b - z )}

x = \frac{- a ^{2} y ^{2} + 2 b z - z ^{2} - b ^{2}}{2 y ( b - z )}

x^{2} + (x - 1)^{2} = 1

(2 x + 5)^{\frac{1}{3}} = 5

(x^{0.16}) + 80 = 122

y - 19 = 2

x + 7 + x + 2 = \frac{15}{( x + 7 )}

What is the answer to solvefor x,z=xy+y*sqrt(x^2-a^2)+b ?
The answer to solvefor x,z=xy+y*sqrt(x^2-a^2)+b is x=(-a^2y^2+2bz-z^2-b^2)/(2y(b-z))