What is the answer to 3sqrt(7x^2)-6x-13sqrt(7)=0 ?

The answer to 3sqrt(7x^2)-6x-13sqrt(7)=0 is x=-(13(7-2sqrt(7)))/9 ,x=(13(2sqrt(7)+7))/9

Solve for x: 3sqrt(7x^2)-6x-13sqrt(7)=0

The solution is x=-(13(7-2sqrt(7)))/9 ,x=(13(2sqrt(7)+7))/9

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3 7 x^{2} - 6 x - 137 = 0

x = - \frac{13 ( 7 - 2 7 )}{9}, x = \frac{13 ( 2 7 + 7 )}{9}

Solution steps

3 7 x^{2} - 6 x - 137 = 0

Remove square roots

63 x^{2} = 36 x^{2} + 1567 x + 1183

Solve

63 x^{2} = 36 x^{2} + 1567 x + 1183 : x = - \frac{13 ( 7 - 2 7 )}{9}, x = \frac{13 ( 2 7 + 7 )}{9}

x = - \frac{13 ( 7 - 2 7 )}{9}, x = \frac{13 ( 2 7 + 7 )}{9}

Verify Solutions:

x = - \frac{13 ( 7 - 2 7 )}{9}

True

, x = \frac{13 ( 2 7 + 7 )}{9}

True

The solutions are

x = - \frac{13 ( 7 - 2 7 )}{9}, x = \frac{13 ( 2 7 + 7 )}{9}

98 - 2 x^{2} + 3 x + 5 + 2 x^{2} - 7 x - 15 = 0

\frac{6 x ^{2}}{( 2 x + 1 + 1 ) ^{2}} = 2 x + x - 1 + 1

c = \frac{1}{( x ^{2} + x - 2 )}

2 x^{2} + 2 5 x - 5 = 0

(\frac{x - 1}{x})^{\frac{1}{2}} + (\frac{1 - 1}{x})^{\frac{1}{2}} = x

What is the answer to 3sqrt(7x^2)-6x-13sqrt(7)=0 ?
The answer to 3sqrt(7x^2)-6x-13sqrt(7)=0 is x=-(13(7-2sqrt(7)))/9 ,x=(13(2sqrt(7)+7))/9
Solve for x: 3sqrt(7x^2)-6x-13sqrt(7)=0
The solution is x=-(13(7-2sqrt(7)))/9 ,x=(13(2sqrt(7)+7))/9