What is the answer to solvefor x,sqrt(2x)+sqrt(3y)=sqrt(5) ?

The answer to solvefor x,sqrt(2x)+sqrt(3y)=sqrt(5) is x=(5-2sqrt(15)sqrt(y)+3y)/2 {0<= y<= 5/3 }

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solvefor x,sqrt(2x)+sqrt(3y)=sqrt(5)

solve for

x, 2 x + 3 y = 5

x = \frac{5 - 2 15 y + 3 y}{2} {0 \leq y \leq \frac{5}{3}}

Solution steps

2 x + 3 y = 5

Expand

2 x + 3 y : 2 x + 3 y

2 x + 3 y = 5

Move

3 y

to the right side

2 x = 5 - 3 y

Square both sides:

2 x = 5 - 215 y + 3 y

2 x = 5 - 215 y + 3 y

Solve

2 x = 5 - 215 y + 3 y : x = \frac{5 - 2 15 y + 3 y}{2}

x = \frac{5 - 2 15 y + 3 y}{2}

Verify Solutions:

x = \frac{5 - 2 15 y + 3 y}{2} {0 \leq y \leq \frac{5}{3}}

The solution is

x = \frac{5 - 2 15 y + 3 y}{2} {0 \leq y \leq \frac{5}{3}}

2 x + x + 2 = 2

x^{\frac{- 3}{2}} = \frac{1}{27}

x^{2} + 2 x + 1 = 0

x^{\frac{3}{4}} = 16

(r^{2} + x^{2})^{\frac{3}{2}} = 8 r^{3}

What is the answer to solvefor x,sqrt(2x)+sqrt(3y)=sqrt(5) ?
The answer to solvefor x,sqrt(2x)+sqrt(3y)=sqrt(5) is x=(5-2sqrt(15)sqrt(y)+3y)/2 {0<= y<= 5/3 }