What is the answer to x^2+2sqrt(x)+1=0 ?

The answer to x^2+2sqrt(x)+1=0 is No Solution for x\in\mathbb{R}

Solve for x: x^2+2sqrt(x)+1=0

The solution is No Solution for x\in\mathbb{R}

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Popular >

x^{2} + 2 x + 1 = 0

No Solution for x \in R

Solution steps

x^{2} + 2 x + 1 = 0

Remove square roots

4 x = x^{4} + 2 x^{2} + 1

Solve

4 x = x^{4} + 2 x^{2} + 1 : x = 1, x \approx 0.29559 \dots

x = 1, x \approx 0.29559 \dots

Verify Solutions:

x = 1

False

, x \approx 0.29559 \dots

False

The solution is

No Solution for x \in R

x^{\frac{3}{4}} = 16

(r^{2} + x^{2})^{\frac{3}{2}} = 8 r^{3}

x^{\frac{1}{3}} + 16 = 0

2 x^{2} + 7 x - 7 = 0

\frac{5}{( x ) - x} = x + 2

What is the answer to x^2+2sqrt(x)+1=0 ?
The answer to x^2+2sqrt(x)+1=0 is No Solution for x\in\mathbb{R}
Solve for x: x^2+2sqrt(x)+1=0
The solution is No Solution for x\in\mathbb{R}