What is the answer to 2x^2+sqrt(7x)-7=0 ?

The answer to 2x^2+sqrt(7x)-7=0 is x\approx 1.39246…

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2x^2+sqrt(7x)-7=0

2 x^{2} + 7 x - 7 = 0

x \approx 1.39246 \dots

Solution steps

2 x^{2} + 7 x - 7 = 0

Remove square roots

7 x = 4 x^{4} - 28 x^{2} + 49

Solve

7 x = 4 x^{4} - 28 x^{2} + 49 : x \approx 2.35127 \dots, x \approx 1.39246 \dots

x \approx 2.35127 \dots, x \approx 1.39246 \dots

Verify Solutions:

x \approx 2.35127 \dots

False

, x \approx 1.39246 \dots

True

The solution is

x \approx 1.39246 \dots

\frac{5}{( x ) - x} = x + 2

9 = x^{\frac{1}{3}}

3 y - 2 = 23 + 4

x^{2} - 3 x = 2

x - 6 = x

What is the answer to 2x^2+sqrt(7x)-7=0 ?
The answer to 2x^2+sqrt(7x)-7=0 is x\approx 1.39246…
Solve for x: 2x^2+sqrt(7x)-7=0
The solution is x\approx 1.39246…