What is the answer to (2k^2)/(3+7k^{1/3)-4}=0 ?

The answer to (2k^2)/(3+7k^{1/3)-4}=0 is k=0

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(2k^2)/(3+7k^{1/3)-4}=0

\frac{2 k ^{2}}{3 + 7 k ^{\frac{1}{3}} - 4} = 0

k = 0

Solution steps

\frac{2 k ^{2}}{3 + 7 k ^{\frac{1}{3}} - 4} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

2 k^{2} = 0

Solve

2 k^{2} = 0 : k = 0

k = 0

Verify Solutions:

k = 0

True

The solution is

k = 0

x - 2 = 18

x^{\frac{1}{2}} = (x - 6)^{2}

2 = m - 4

x^{2} - 4 - x^{2} + 4 = 0

3 - x = 1

What is the answer to (2k^2)/(3+7k^{1/3)-4}=0 ?
The answer to (2k^2)/(3+7k^{1/3)-4}=0 is k=0
Solve for k: (2k^2)/(3+7k^{1/3)-4}=0
The solution is k=0