What is the answer to |x^2-x+1|=|x^2-x-1| ?

The answer to |x^2-x+1|=|x^2-x-1| is x=0\lor x=1

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|x^2-x+1|=|x^2-x-1|

x^{2} - x + 1 = x^{2} - x - 1

x = 0 or x = 1

Solution steps

x^{2} - x + 1 = x^{2} - x - 1

Find positive and negative intervals

x \leq \frac{- 5 + 1}{2}, \frac{- 5 + 1}{2} < x < \frac{5 + 1}{2}, x \geq \frac{5 + 1}{2}

Solve the inequality for each interval

No Solution or (x = 0 or x = 1)

x = 0 or x = 1

x^{2} - 5 x + 2 = 4

∣ x ∣ + ∣ x - 2 ∣ = 2

x^{2} - ∣ x ∣ - 2 = 0

x^{2} - x - 6 = x + 2

∣ x - 3 ∣ + ∣ 4 - x ∣ = 1

What is the answer to |x^2-x+1|=|x^2-x-1| ?
The answer to |x^2-x+1|=|x^2-x-1| is x=0\lor x=1
Solve for x: |x^2-x+1|=|x^2-x-1|
The solution is x=0\lor x=1