What is the answer to |x^2-4x+2|=((5x-4))/3 ?

The answer to |x^2-4x+2|=((5x-4))/3 is x=2\lor x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

|x^2-4x+2|=((5x-4))/3

x^{2} - 4 x + 2 = \frac{( 5 x - 4 )}{3}

x = 2 or x = 5

Solution steps

x^{2} - 4 x + 2 = \frac{5 x - 4}{3}

Find positive and negative intervals

x \leq - 2 + 2, - 2 + 2 < x < 2 + 2, x \geq 2 + 2

Solve the inequality for each interval

No Solution or x = 2 or x = 5

x = 2 or x = 5

∣ x ∣ - 2 ∣ x + 1 ∣ + 3 ∣ x + 2 ∣ = 0

x^{3} + x^{2} + x + 1 = x^{3} + 1 + x^{2} + x

∣ 2 x - 3 ∣ = ∣ 3 x + 5 ∣

2 ∣ x + 1 ∣^{2} - ∣ x + 1 ∣ = 3

∣ x + 2 ∣ + ∣ x - 3 ∣ + 2 = 0

What is the answer to |x^2-4x+2|=((5x-4))/3 ?
The answer to |x^2-4x+2|=((5x-4))/3 is x=2\lor x=5
Solve for x: |x^2-4x+2|=((5x-4))/3
The solution is x=2\lor x=5