What is the answer to |x^2-1|=x+3 ?

The answer to |x^2-1|=x+3 is x=(1-sqrt(17))/2 \lor x=(1+sqrt(17))/2

Solve for x: |x^2-1|=x+3

The solution is x=(1-sqrt(17))/2 \lor x=(1+sqrt(17))/2

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x^{2} - 1 = x + 3

x = \frac{1 - 17}{2} or x = \frac{1 + 17}{2}

Decimal Notation

x = - 1.56155 \dots, x = 2.56155 \dots

Solution steps

x^{2} - 1 = x + 3

Find positive and negative intervals

x \leq - 1, - 1 < x < 1, x \geq 1

Solve the inequality for each interval

x = \frac{1 - 17}{2} or No Solution or x = \frac{1 + 17}{2}

x = \frac{1 - 17}{2} or x = \frac{1 + 17}{2}

∣ 10 x + 20 ∣ \cdot ∣ 4 x + 8 ∣ = 360

x^{2} - 3 x ∣ + 2 ∣ = x^{2} - 2 x

x^{2} - 4 x + 3 = - x^{2} - 5 x + 4

∣ x + 2 ∣ + ∣ 2 x + 1 ∣ - 3 ∣ x - 1 ∣ = 6

∣ x + 4 ∣ - ∣ x ∣ = 4

What is the answer to |x^2-1|=x+3 ?
The answer to |x^2-1|=x+3 is x=(1-sqrt(17))/2 \lor x=(1+sqrt(17))/2
Solve for x: |x^2-1|=x+3
The solution is x=(1-sqrt(17))/2 \lor x=(1+sqrt(17))/2