What is the answer to |x^2-4x+3|=-|x^2-5x+4| ?

The answer to |x^2-4x+3|=-|x^2-5x+4| is x=1

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|x^2-4x+3|=-|x^2-5x+4|

x^{2} - 4 x + 3 = - x^{2} - 5 x + 4

x = 1

Solution steps

x^{2} - 4 x + 3 = - x^{2} - 5 x + 4

Find positive and negative intervals

x \leq 1, 1 < x < 3, 3 \leq x < 4, x \geq 4

Solve the inequality for each interval

x = 1 or No Solution

x = 1

∣ x + 2 ∣ + ∣ 2 x + 1 ∣ - 3 ∣ x - 1 ∣ = 6

∣ x + 4 ∣ - ∣ x ∣ = 4

x^{2} - 9 = ∣ 3 - 4 x ∣ + 9

∣ x - 1 ∣ = ∣ 2 x - 1 ∣

∣ x - 2 ∣ + ∣ x - 6 ∣ = 2

What is the answer to |x^2-4x+3|=-|x^2-5x+4| ?
The answer to |x^2-4x+3|=-|x^2-5x+4| is x=1
Solve for x: |x^2-4x+3|=-|x^2-5x+4|
The solution is x=1