What is the answer to |x^2-x|+|x+1|=5 ?

The answer to |x^2-x|+|x+1|=5 is x=1-sqrt(7)\lor x=2

Solve for x: |x^2-x|+|x+1|=5

The solution is x=1-sqrt(7)\lor x=2

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x^{2} - x + ∣ x + 1 ∣ = 5

x = 1 - 7 or x = 2

Decimal Notation

x = - 1.64575 \dots, x = 2

Solution steps

x^{2} - x + ∣ x + 1 ∣ = 5

Find positive and negative intervals

x < - 1, - 1 \leq x \leq 0, 0 < x < 1, x \geq 1

Solve the inequality for each interval

x = 1 - 7 or No Solution or x = 2

x = 1 - 7 or x = 2

∣ x ∣ + ∣ y ∣ = 4

∣ x ∣ + x^{3} = 0

(3 x - 2)^{2} - 5 ∣ 3 x - 2 ∣ - 6 = 0

x^{2} - 3 x + 2 = ∣ 2 x - 3 ∣

7 (∣ x ∣ + 6) = 7 (∣ x ∣ + 5)

What is the answer to |x^2-x|+|x+1|=5 ?
The answer to |x^2-x|+|x+1|=5 is x=1-sqrt(7)\lor x=2
Solve for x: |x^2-x|+|x+1|=5
The solution is x=1-sqrt(7)\lor x=2