What is the answer to |x^2-x-2|=2+x-x^2 ?

The answer to |x^2-x-2|=2+x-x^2 is -1<= x<= 2

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|x^2-x-2|=2+x-x^2

x^{2} - x - 2 = 2 + x - x^{2}

- 1 \leq x \leq 2

Solution steps

x^{2} - x - 2 = 2 + x - x^{2}

Find positive and negative intervals

x \leq - 1, - 1 < x < 2, x \geq 2

Solve the inequality for each interval

x = - 1 or - 1 < x < 2 or x = 2

Merge Overlapping Intervals

- 1 \leq x \leq 2

x^{2} - 4 x + 3 = 3 x^{2} - 5 x + 4

2 + 3 ∣ 2 x + 1 ∣ = 4

∣ x - 1 ∣ - ∣ x - 2 ∣ = 10

x^{2} + 3 ∣ x ∣ + 2 = 0

∣ x - 3 ∣ = x - 3

What is the answer to |x^2-x-2|=2+x-x^2 ?
The answer to |x^2-x-2|=2+x-x^2 is -1<= x<= 2
Solve for x: |x^2-x-2|=2+x-x^2
The solution is -1<= x<= 2