What is the answer to |x^2-5x+6|=2x-3 ?

The answer to |x^2-5x+6|=2x-3 is x=(7-sqrt(13))/2 \lor x=(7+sqrt(13))/2

Solve for x: |x^2-5x+6|=2x-3

The solution is x=(7-sqrt(13))/2 \lor x=(7+sqrt(13))/2

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x^{2} - 5 x + 6 = 2 x - 3

x = \frac{7 - 13}{2} or x = \frac{7 + 13}{2}

Solution steps

x^{2} - 5 x + 6 = 2 x - 3

Find positive and negative intervals

x \leq 2, 2 < x < 3, x \geq 3

Solve the inequality for each interval

x = \frac{7 - 13}{2} or No Solution or x = \frac{7 + 13}{2}

x = \frac{7 - 13}{2} or x = \frac{7 + 13}{2}

\frac{( 4 w - 1 )}{6} = \frac{( 2 w )}{3} + \frac{1}{4}

∣ 2 x - 1 ∣ + x = 3

b ∣ 3 x + 6 ∣ - ∣ 2 x - 1 ∣ = 5

x^{2} - 1 = ∣ x + 3 ∣

∣ 5 u + 10 ∣ = 15 u

What is the answer to |x^2-5x+6|=2x-3 ?
The answer to |x^2-5x+6|=2x-3 is x=(7-sqrt(13))/2 \lor x=(7+sqrt(13))/2
Solve for x: |x^2-5x+6|=2x-3
The solution is x=(7-sqrt(13))/2 \lor x=(7+sqrt(13))/2