What is the answer to |x^2-1|=|x+3| ?

The answer to |x^2-1|=|x+3| is x=(1-sqrt(17))/2 \lor x=(1+sqrt(17))/2

Solve for x: |x^2-1|=|x+3|

The solution is x=(1-sqrt(17))/2 \lor x=(1+sqrt(17))/2

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x^{2} - 1 = ∣ x + 3 ∣

x = \frac{1 - 17}{2} or x = \frac{1 + 17}{2}

Solution steps

x^{2} - 1 = ∣ x + 3 ∣

Find positive and negative intervals

x < - 3, - 3 \leq x \leq - 1, - 1 < x < 1, x \geq 1

Solve the inequality for each interval

No Solution or x = \frac{1 - 17}{2} or x = \frac{1 + 17}{2}

x = \frac{1 - 17}{2} or x = \frac{1 + 17}{2}

∣ 5 u + 10 ∣ = 15 u

x^{2} - 1 = ∣ 2 x - 1 ∣

∣ 2 - 3 x ∣ - x = 0

∣ 15 x - 7 ∣ - ∣ 5 x + 3 ∣ = 0

∣ 4 x + 7 ∣ - 3 = 21

What is the answer to |x^2-1|=|x+3| ?
The answer to |x^2-1|=|x+3| is x=(1-sqrt(17))/2 \lor x=(1+sqrt(17))/2
Solve for x: |x^2-1|=|x+3|
The solution is x=(1-sqrt(17))/2 \lor x=(1+sqrt(17))/2