What is the answer to |x^2+x+2|-|x^2-x+1|=|2x+1| ?

The answer to |x^2+x+2|-|x^2-x+1|=|2x+1| is x>=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

|x^2+x+2|-|x^2-x+1|=|2x+1|

x^{2} + x + 2 - x^{2} - x + 1 = ∣ 2 x + 1 ∣

x \geq - \frac{1}{2}

Solution steps

x^{2} + x + 2 - x^{2} - x + 1 = ∣ 2 x + 1 ∣

Find positive and negative intervals

x < - \frac{1}{2}, x \geq - \frac{1}{2}

Solve the inequality for each interval

No Solution or x \geq - \frac{1}{2}

Merge Overlapping Intervals

x \geq - \frac{1}{2}

\frac{x}{2 + 3} \cdot (5 - 6 x) + (12 x - 2) \frac{x}{4 + 3} = 0

x^{2} - 4 x - 20 = 1

∣ 2 x + 1 ∣ - 2 ∣ x - 2 ∣ = 5

∣ x - 1 ∣ + ∣ x - 4 ∣ = 3

∣ 2 x ∣ + ∣ x - 5 ∣ = 8

What is the answer to |x^2+x+2|-|x^2-x+1|=|2x+1| ?
The answer to |x^2+x+2|-|x^2-x+1|=|2x+1| is x>=-1/2
Solve for x: |x^2+x+2|-|x^2-x+1|=|2x+1|
The solution is x>=-1/2