What is the answer to |x-1|+|x-2|+|x-3|+|x-4|=4 ?

The answer to |x-1|+|x-2|+|x-3|+|x-4|=4 is 2<= x<= 3

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|x-1|+|x-2|+|x-3|+|x-4|=4

∣ x - 1 ∣ + ∣ x - 2 ∣ + ∣ x - 3 ∣ + ∣ x - 4 ∣ = 4

2 \leq x \leq 3

Solution steps

∣ x - 1 ∣ + ∣ x - 2 ∣ + ∣ x - 3 ∣ + ∣ x - 4 ∣ = 4

Find positive and negative intervals

x < 1, 1 \leq x < 2, 2 \leq x < 3, 3 \leq x < 4, x \geq 4

Solve the inequality for each interval

No Solution or 2 \leq x < 3 or x = 3

Merge Overlapping Intervals

2 \leq x \leq 3

∣ x + 2 ∣ = - 17

(x - 1) (∣ x ∣ - 1) = \frac{- 1}{2}

\frac{x + 1}{2} - 6 = - 2

x^{2} - 2 x + ∣ 3 x - 6 ∣ = 5 x - 6 - x^{2}

x^{2} + 12 x - 28 = 9 x

What is the answer to |x-1|+|x-2|+|x-3|+|x-4|=4 ?
The answer to |x-1|+|x-2|+|x-3|+|x-4|=4 is 2<= x<= 3
Solve for x: |x-1|+|x-2|+|x-3|+|x-4|=4
The solution is 2<= x<= 3