What is the answer to |x^2+12x-28|=9x ?

The answer to |x^2+12x-28|=9x is x=(sqrt(553)-21)/2 \lor x=4

Solve for x: |x^2+12x-28|=9x

The solution is x=(sqrt(553)-21)/2 \lor x=4

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x^{2} + 12 x - 28 = 9 x

x = \frac{553 - 21}{2} or x = 4

Decimal Notation

x = 1.25797 \dots, x = 4

Solution steps

x^{2} + 12 x - 28 = 9 x

Find positive and negative intervals

x \leq - 14, - 14 < x < 2, x \geq 2

Solve the inequality for each interval

No Solution or x = \frac{553 - 21}{2} or x = 4

x = \frac{553 - 21}{2} or x = 4

∣ a + 15 ∣ = 2, a ∣ b - a ∣ = 2 b

11 ∣ 2 x + 3 ∣ - ∣ 2 x - 5 ∣ = 6

- x^{2} + x - 1 = ∣ x + 5 ∣

∣ n ∣ + ∣ n - 4 ∣ + ∣ n - 6 ∣ = 10

∣ x ∣ + ∣ x + 5 ∣ = 5

What is the answer to |x^2+12x-28|=9x ?
The answer to |x^2+12x-28|=9x is x=(sqrt(553)-21)/2 \lor x=4
Solve for x: |x^2+12x-28|=9x
The solution is x=(sqrt(553)-21)/2 \lor x=4