What is the answer to x^2-4x+|x^2-5|-1=0 ?

The answer to x^2-4x+|x^2-5|-1=0 is x=1\lor x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-4x+|x^2-5|-1=0

x^{2} - 4 x + x^{2} - 5 - 1 = 0

x = 1 or x = 3

Solution steps

x^{2} - 4 x + x^{2} - 5 - 1 = 0

Find positive and negative intervals

x \leq - 5, - 5 < x < 5, x \geq 5

Solve the inequality for each interval

No Solution or x = 1 or x = 3

x = 1 or x = 3

2 ∣ n + 7 ∣ = ∣ 4 n + 8 ∣

∣ x - 2 ∣ + ∣ x - 3 ∣ + ∣ x + 1 ∣ = 7

∣ 3 x - 5 ∣ - ∣ 1 - x ∣ = 0

∣ x + 2 ∣ + ∣ x + 3 ∣ = x

∣ x - 2 ∣ + ∣ 2 x - 3 ∣ + ∣ 3 x - 8 ∣ = 18

What is the answer to x^2-4x+|x^2-5|-1=0 ?
The answer to x^2-4x+|x^2-5|-1=0 is x=1\lor x=3
Solve for x: x^2-4x+|x^2-5|-1=0
The solution is x=1\lor x=3