What is the answer to |x^2+x-2|=x^2+x-2 ?

The answer to |x^2+x-2|=x^2+x-2 is x = 1

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|x^2+x-2|=x^2+x-2

x^{2} + x - 2 = x^{2} + x - 2

x \leq - 2 or x \geq 1

Solution steps

x^{2} + x - 2 = x^{2} + x - 2

Find positive and negative intervals

x \leq - 2, - 2 < x < 1, x \geq 1

Solve the inequality for each interval

x \leq - 2 or No Solution or x \geq 1

Merge Overlapping Intervals

x \leq - 2 or x \geq 1

2 x^{2} - 4 = x^{2}

∣ a ∣ = 2, ∣ b ∣ = 3, ∣ 3 a + b ∣ = 7

x + \frac{5}{6} = \frac{1}{5} - \frac{2}{3} + \frac{( - 3 )}{4}

∣ 2 x - 1 ∣ = 3 - 2 x

∣ x - 1 ∣ + ∣ x - 2 ∣ + ∣ x - 3 ∣ = 4

What is the answer to |x^2+x-2|=x^2+x-2 ?
The answer to |x^2+x-2|=x^2+x-2 is x<=-2\lor x>= 1
Solve for x: |x^2+x-2|=x^2+x-2
The solution is x<=-2\lor x>= 1