What is the answer to |x-4|+|2x+1|-|3x|=3 ?

The answer to |x-4|+|2x+1|-|3x|=3 is x<=-1/2 \lor x=1

Solve for x: |x-4|+|2x+1|-|3x|=3

The solution is x<=-1/2 \lor x=1

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The solution is x<=-1/2 \lor x=1

∣ x - 4 ∣ + ∣ 2 x + 1 ∣ - ∣ 3 x ∣ = 3

x \leq - \frac{1}{2} or x = 1

Solution steps

∣ x - 4 ∣ + ∣ 2 x + 1 ∣ - ∣ 3 x ∣ = 3

Find positive and negative intervals

x < - \frac{1}{2}, - \frac{1}{2} \leq x < 0, 0 \leq x < 4, x \geq 4

Solve the inequality for each interval

x < - \frac{1}{2} or x = - \frac{1}{2} or x = 1 or No Solution

Merge Overlapping Intervals

x \leq - \frac{1}{2} or x = 1

x^{2} - x - 12 = x + 12 - x^{2}

∣ 6 x + 9 ∣ = ∣ 3 x - 7 ∣

∣ 3 x - 4 ∣ = ∣ x ∣

2 x^{2} + 5 + ∣ 2 x - 6 ∣ = 8

5 - ∣ 2 x + 1 ∣ = 0

What is the answer to |x-4|+|2x+1|-|3x|=3 ?
The answer to |x-4|+|2x+1|-|3x|=3 is x<=-1/2 \lor x=1
Solve for x: |x-4|+|2x+1|-|3x|=3
The solution is x<=-1/2 \lor x=1