What is the answer to 2*|x-2|-3*|2x+4|=5-2*(1-3x) ?

The answer to 2*|x-2|-3*|2x+4|=5-2*(1-3x) is x=-11/14

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2|x-2|-3|2x+4|=5-2*(1-3x)

2 \cdot ∣ x - 2 ∣ - 3 \cdot ∣ 2 x + 4 ∣ = 5 - 2 \cdot (1 - 3 x)

x = - \frac{11}{14}

Decimal Notation

x = - 0.78571 \dots

Solution steps

2 ∣ x - 2 ∣ - 3 ∣ 2 x + 4 ∣ = 5 - 2 (1 - 3 x)

Find positive and negative intervals

x < - 2, - 2 \leq x < 2, x \geq 2

Solve the inequality for each interval

No Solution or x = - \frac{11}{14}

x = - \frac{11}{14}

∣ 2 x - 1 ∣ = x + 1

x^{2} - 1 + ∣ x ∣ = 2

3 - 2 ∣ x + 1 ∣ = 1

(x^{2} + ∣ x - 1 ∣) = x (x + 2)

(d) ∣ x - 3 ∣ + ∣ x + 5 ∣ = 10

What is the answer to 2*|x-2|-3*|2x+4|=5-2*(1-3x) ?
The answer to 2*|x-2|-3*|2x+4|=5-2*(1-3x) is x=-11/14
Solve for x: 2*|x-2|-3*|2x+4|=5-2*(1-3x)
The solution is x=-11/14