What is the answer to 1|x+2|=2(3-x) ?

The answer to 1|x+2|=2(3-x) is x= 4/3

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1|x+2|=2(3-x)

1 ∣ x + 2 ∣ = 2 (3 - x)

x = \frac{4}{3}

Decimal Notation

x = 1.33333 \dots

Solution steps

1 \cdot ∣ x + 2 ∣ = 2 (3 - x)

Find positive and negative intervals

x < - 2, x \geq - 2

Solve the inequality for each interval

No Solution or x = \frac{4}{3}

x = \frac{4}{3}

lo g_{2} (x - 6) = 6

ln (x) = - 1

ln (x) = 1

lo g_{2} (2 x + 4) = 4

5 lo g_{3} (4 x - 7) = 3