What is the answer to 5log_{3}(4x-7)=3 ?

The answer to 5log_{3}(4x-7)=3 is x=(3^{3/5}+7)/4

Solve for x: 5log_{3}(4x-7)=3

The solution is x=(3^{3/5}+7)/4

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5 lo g_{3} (4 x - 7) = 3

x = \frac{3 ^{\frac{3}{5}} + 7}{4}

Decimal Notation

x = 2.23329 \dots

Solution steps

5 lo g_{3} (4 x - 7) = 3

Divide both sides by

5

lo g_{3} (4 x - 7) = \frac{3}{5}

Apply log rules

4 x - 7 = 3^{\frac{3}{5}}

Solve

4 x - 7 = 3^{\frac{3}{5}} : x = \frac{3 ^{\frac{3}{5}} + 7}{4}

x = \frac{3 ^{\frac{3}{5}} + 7}{4}

Verify Solutions:

x = \frac{3 ^{\frac{3}{5}} + 7}{4}

True

The solution is

x = \frac{3 ^{\frac{3}{5}} + 7}{4}

ln (x) = 1 + 3 ln (x)

x^{2} lo g_{10} (x) = 10 x^{2}

lo g_{6} (x + 7) - lo g_{6} (x) = 2

lo g_{10} (x + 1) = lo g_{10} (x - 1) + 3

lo g_{2} (4 x - 6) = 1

What is the answer to 5log_{3}(4x-7)=3 ?
The answer to 5log_{3}(4x-7)=3 is x=(3^{3/5}+7)/4
Solve for x: 5log_{3}(4x-7)=3
The solution is x=(3^{3/5}+7)/4