What is the answer to log_{6}(x+7)-log_{6}(x)=2 ?

The answer to log_{6}(x+7)-log_{6}(x)=2 is x= 1/5

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log_{6}(x+7)-log_{6}(x)=2

lo g_{6} (x + 7) - lo g_{6} (x) = 2

x = \frac{1}{5}

Decimal Notation

x = 0.2

Solution steps

lo g_{6} (x + 7) - lo g_{6} (x) = 2

Add

lo g_{6} (x)

to both sides

lo g_{6} (x + 7) - lo g_{6} (x) + lo g_{6} (x) = 2 + lo g_{6} (x)

Simplify

lo g_{6} (x + 7) = 2 + lo g_{6} (x)

Apply log rules

x + 7 = 36 x

Solve

x + 7 = 36 x : x = \frac{1}{5}

x = \frac{1}{5}

Verify Solutions:

x = \frac{1}{5}

True

The solution is

x = \frac{1}{5}

lo g_{10} (x + 1) = lo g_{10} (x - 1) + 3

lo g_{2} (4 x - 6) = 1

lo g_{10} (x) = 2

ln (x) = 0

x, ln ∣ x ∣ + v + ln ∣ v - 1 ∣ = ln ∣ c ∣

What is the answer to log_{6}(x+7)-log_{6}(x)=2 ?
The answer to log_{6}(x+7)-log_{6}(x)=2 is x= 1/5
Solve for x: log_{6}(x+7)-log_{6}(x)=2
The solution is x= 1/5