What is the answer to log_{10}((x+3)^2)-2=log_{10}(1/((x^2))) ?

The answer to log_{10}((x+3)^2)-2=log_{10}(1/((x^2))) is x=2,x=-5

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log_{10}((x+3)^2)-2=log_{10}(1/((x^2)))

lo g_{10} ((x + 3)^{2}) - 2 = lo g_{10} (\frac{1}{( x ^{2} )})

x = 2, x = - 5

Solution steps

lo g_{10} ((x + 3)^{2}) - 2 = lo g_{10} (\frac{1}{( x ^{2} )})

Apply log rules

(x + 3)^{2} x^{2} = 100

Solve

(x + 3)^{2} x^{2} = 100 : x = 2, x = - 5

x = 2, x = - 5

Verify Solutions:

x = 2

True

, x = - 5

True

The solutions are

x = 2, x = - 5

a, lo g_{2} (a) - 3 lo g_{2} (b) = 2

lo g_{3} (2 x + 3) = 5

lo g_{2} (x - 2) + lo g_{2} (x + 1) = 2

ln^{2} (x) = (ln (x))^{2}

lo g_{5} (x) = 520 - lo g_{54} (x)

What is the answer to log_{10}((x+3)^2)-2=log_{10}(1/((x^2))) ?
The answer to log_{10}((x+3)^2)-2=log_{10}(1/((x^2))) is x=2,x=-5
Solve for x: log_{10}((x+3)^2)-2=log_{10}(1/((x^2)))
The solution is x=2,x=-5