What is the answer to log_{10}(x)+log_{10}(x-21)=2 ?

The answer to log_{10}(x)+log_{10}(x-21)=2 is x=25

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log_{10}(x)+log_{10}(x-21)=2

lo g_{10} (x) + lo g_{10} (x - 21) = 2

x = 25

Solution steps

lo g_{10} (x) + lo g_{10} (x - 21) = 2

Apply log rules

x (x - 21) = 100

Solve

x (x - 21) = 100 : x = 25, x = - 4

x = 25, x = - 4

Verify Solutions:

x = 25

True

, x = - 4

False

The solution is

x = 25

lo g_{3} (2 x + 1) + lo g_{3} (x + 8) = 3

ln (x - 1) = 1

4 \cdot lo g_{10} (x) = 3 \cdot (- 0.6655)

b, 2 lo g_{10} (9 a) - 3 lo g_{3} (b) = 1

lo g_{4} (5 x - 1) = 3

What is the answer to log_{10}(x)+log_{10}(x-21)=2 ?
The answer to log_{10}(x)+log_{10}(x-21)=2 is x=25
Solve for x: log_{10}(x)+log_{10}(x-21)=2
The solution is x=25