What is the answer to log_{2}(x+3)-2log_{2}(x)=4 ?

The answer to log_{2}(x+3)-2log_{2}(x)=4 is x=(1+sqrt(193))/(32)

Solve for x: log_{2}(x+3)-2log_{2}(x)=4

The solution is x=(1+sqrt(193))/(32)

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lo g_{2} (x + 3) - 2 lo g_{2} (x) = 4

x = \frac{1 + 193}{32}

Decimal Notation

x = 0.46538 \dots

Solution steps

lo g_{2} (x + 3) - 2 lo g_{2} (x) = 4

Apply log rules

x + 3 = 16 x^{2}

Solve

x + 3 = 16 x^{2} : x = \frac{1 + 193}{32}, x = \frac{1 - 193}{32}

x = \frac{1 + 193}{32}, x = \frac{1 - 193}{32}

Verify Solutions:

x = \frac{1 + 193}{32}

True

, x = \frac{1 - 193}{32}

False

The solution is

x = \frac{1 + 193}{32}

ln (p^{2}) = ln (10 p) - 3

\frac{x}{lo g _{10} ( x ) ( \frac{1}{32} )} = 5

lo g_{2} (x) = 5

lo g_{10} (x) + lo g_{10} (x + 3) = 3

lo g_{2} (lo g_{3} (x)) = 4

What is the answer to log_{2}(x+3)-2log_{2}(x)=4 ?
The answer to log_{2}(x+3)-2log_{2}(x)=4 is x=(1+sqrt(193))/(32)
Solve for x: log_{2}(x+3)-2log_{2}(x)=4
The solution is x=(1+sqrt(193))/(32)