What is the answer to log_{10}(2x-3)=2 ?

The answer to log_{10}(2x-3)=2 is x= 103/2

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log_{10}(2x-3)=2

lo g_{10} (2 x - 3) = 2

x = \frac{103}{2}

Decimal Notation

x = 51.5

Solution steps

lo g_{10} (2 x - 3) = 2

Apply log rules

2 x - 3 = 100

Solve

2 x - 3 = 100 : x = \frac{103}{2}

x = \frac{103}{2}

lo g_{10} ((5 x - 3)^{2}) + lo g_{10} ((2 x + 3)^{3}) = 2

ln (x + 1) = 2 + ln (x - 1)

lo g_{2} (y) - 8 \cdot lo g_{y} (2) = 2

lo g_{10} (x - 2) + lo g_{10} (x - 3) = lo g_{10} (2)

lo g_{2} (x + 5) - lo g_{2} (x - 1) = 2

What is the answer to log_{10}(2x-3)=2 ?
The answer to log_{10}(2x-3)=2 is x= 103/2
Solve for x: log_{10}(2x-3)=2
The solution is x= 103/2