What is the answer to log_{2}(x+5)-log_{2}(x-1)=2 ?

The answer to log_{2}(x+5)-log_{2}(x-1)=2 is x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(x+5)-log_{2}(x-1)=2

lo g_{2} (x + 5) - lo g_{2} (x - 1) = 2

x = 3

Solution steps

lo g_{2} (x + 5) - lo g_{2} (x - 1) = 2

Add

lo g_{2} (x - 1)

to both sides

lo g_{2} (x + 5) - lo g_{2} (x - 1) + lo g_{2} (x - 1) = 2 + lo g_{2} (x - 1)

Simplify

lo g_{2} (x + 5) = 2 + lo g_{2} (x - 1)

Apply log rules

x + 5 = 4 (x - 1)

Solve

x + 5 = 4 (x - 1) : x = 3

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

b, lo g_{3} (\frac{a}{b}) = lo g_{27} (a) + 1

lo g_{9} (x - 5) + lo g_{9} (x + 3) = 1

lo g_{a} (x) = \frac{1}{b \cdot lo g _{a} ( c )}

lo g_{2} (x + 5) = 3

lo g_{3} (3 x + 4) = 3

What is the answer to log_{2}(x+5)-log_{2}(x-1)=2 ?
The answer to log_{2}(x+5)-log_{2}(x-1)=2 is x=3
Solve for x: log_{2}(x+5)-log_{2}(x-1)=2
The solution is x=3