What is the answer to solvefor b,log_{3}(a/b)=log_{27}(a)+1 ?

The answer to solvefor b,log_{3}(a/b)=log_{27}(a)+1 is b=(a^{2/3})/3 {a>0}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor b,log_{3}(a/b)=log_{27}(a)+1

solve for

b, lo g_{3} (\frac{a}{b}) = lo g_{27} (a) + 1

b = \frac{a ^{\frac{2}{3}}}{3} {a > 0}

Solution steps

lo g_{3} (\frac{a}{b}) = lo g_{27} (a) + 1

Apply log rules

\frac{a}{b} = 3^{l o g_{27} (a) + 1}

Multiply both sides by

b

\frac{a}{b} b = 3^{l o g_{27} (a) + 1} b

Apply log rules

Solve

b = \frac{a ^{\frac{2}{3}}}{3}

Verify Solutions:

b = \frac{a ^{\frac{2}{3}}}{3} {a > 0}

The solution is

b = \frac{a ^{\frac{2}{3}}}{3} {a > 0}

lo g_{9} (x - 5) + lo g_{9} (x + 3) = 1

lo g_{a} (x) = \frac{1}{b \cdot lo g _{a} ( c )}

lo g_{2} (x + 5) = 3

lo g_{3} (3 x + 4) = 3

lo g_{3} (2 x + 5) = 4

What is the answer to solvefor b,log_{3}(a/b)=log_{27}(a)+1 ?
The answer to solvefor b,log_{3}(a/b)=log_{27}(a)+1 is b=(a^{2/3})/3 {a>0}