What is the answer to log_{2}(3-x)=log_{2}(2x+18) ?

The answer to log_{2}(3-x)=log_{2}(2x+18) is x=-5

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log_{2}(3-x)=log_{2}(2x+18)

lo g_{2} (3 - x) = lo g_{2} (2 x + 18)

x = - 5

Solution steps

lo g_{2} (3 - x) = lo g_{2} (2 x + 18)

Apply log rules

3 - x = 2 x + 18

Solve

3 - x = 2 x + 18 : x = - 5

x = - 5

Verify Solutions:

x = - 5

True

The solution is

x = - 5

lo g_{2} (8 x - 26) + lo g_{2} (4 x - 20) = 2

3 = lo g_{10} (x) 125

lo g_{3} (x) = \frac{- 3}{2}

lo g_{25} (2 x - 1) = \frac{1}{2}

lo g_{10} (x) = 4

What is the answer to log_{2}(3-x)=log_{2}(2x+18) ?
The answer to log_{2}(3-x)=log_{2}(2x+18) is x=-5
Solve for x: log_{2}(3-x)=log_{2}(2x+18)
The solution is x=-5