What is the answer to ln(x)+ln(x-4)=ln(4) ?

The answer to ln(x)+ln(x-4)=ln(4) is x=2(1+sqrt(2))

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ln(x)+ln(x-4)=ln(4)

ln (x) + ln (x - 4) = ln (4)

x = 2 (1 + 2)

Decimal Notation

x = 4.82842 \dots

Solution steps

ln (x) + ln (x - 4) = ln (4)

Apply log rules

x (x - 4) = 4

Solve

x (x - 4) = 4 : x = 2 (1 + 2), x = 2 (1 - 2)

x = 2 (1 + 2), x = 2 (1 - 2)

Verify Solutions:

x = 2 (1 + 2)

True

, x = 2 (1 - 2)

False

The solution is

x = 2 (1 + 2)

(lo g_{10} (x))^{2} + lo g_{10} (x) = 2

lo g_{7} (x^{2} - 9) = 1

ln (y) = 5

lo g_{2} (6) + 3 \cdot lo g_{2} (p) = 3

(x) = 50 + 8 lo g_{10} (14 + 3 x)

What is the answer to ln(x)+ln(x-4)=ln(4) ?
The answer to ln(x)+ln(x-4)=ln(4) is x=2(1+sqrt(2))
Solve for x: ln(x)+ln(x-4)=ln(4)
The solution is x=2(1+sqrt(2))