What is the answer to log_{3}((x+2)^2)+1=7 ?

The answer to log_{3}((x+2)^2)+1=7 is x=25,x=-29

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log_{3}((x+2)^2)+1=7

lo g_{3} ((x + 2)^{2}) + 1 = 7

x = 25, x = - 29

Solution steps

lo g_{3} ((x + 2)^{2}) + 1 = 7

Move

1

to the right side

lo g_{3} ((x + 2)^{2}) = 6

Apply log rules

(x + 2)^{2} = 729

Solve

(x + 2)^{2} = 729 : x = 25, x = - 29

x = 25, x = - 29

Verify Solutions:

x = 25

True

, x = - 29

True

The solutions are

x = 25, x = - 29

lo g_{10} (x^{2} - 3 x + 1) = lo g_{10} (- 3 x + 10)

x, lo g_{6} (x) + lo g_{6} (y) = 1

lo g_{2} (x - 4) = 0

lo g_{3} (2 x) = 2

a, lo g_{3} (a) - 2 \cdot lo g_{10} (b) = 3

What is the answer to log_{3}((x+2)^2)+1=7 ?
The answer to log_{3}((x+2)^2)+1=7 is x=25,x=-29
Solve for x: log_{3}((x+2)^2)+1=7
The solution is x=25,x=-29