What is the answer to solvefor a,log_{3}(a)-2*log_{10}(b)=3 ?

The answer to solvefor a,log_{3}(a)-2*log_{10}(b)=3 is a=3^{3+2log_{10}(b)} {b>0}

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solvefor a,log_{3}(a)-2*log_{10}(b)=3

solve for

a, lo g_{3} (a) - 2 \cdot lo g_{10} (b) = 3

a = 3^{3 + 2 l o g_{10} (b)} {b > 0}

Solution steps

lo g_{3} (a) - 2 lo g_{10} (b) = 3

Move

2 lo g_{10} (b)

to the right side

lo g_{3} (a) = 3 + 2 lo g_{10} (b)

Apply log rules

a = 3^{3 + 2 l o g_{10} (b)}

Verify Solutions:

a = 3^{3 + 2 l o g_{10} (b)} {b > 0}

The solution is

a = 3^{3 + 2 l o g_{10} (b)} {b > 0}

ln (\frac{( x + 1 )}{x}) + ln (2) = ln (x + 3)

lo g_{2} (lo g_{4} (lo g_{5} (x))) = 0

9 = ln (x)

lo g_{10} (125 x) = \frac{1}{3}

lo g_{5} (4 - x) - 2 lo g_{5} (x) = 1

What is the answer to solvefor a,log_{3}(a)-2*log_{10}(b)=3 ?
The answer to solvefor a,log_{3}(a)-2*log_{10}(b)=3 is a=3^{3+2log_{10}(b)} {b>0}