What is the answer to log_{5}(4-x)-2log_{5}(x)=1 ?

The answer to log_{5}(4-x)-2log_{5}(x)=1 is x= 4/5

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log_{5}(4-x)-2log_{5}(x)=1

lo g_{5} (4 - x) - 2 lo g_{5} (x) = 1

x = \frac{4}{5}

Decimal Notation

x = 0.8

Solution steps

lo g_{5} (4 - x) - 2 lo g_{5} (x) = 1

Apply log rules

4 - x = 5 x^{2}

Solve

4 - x = 5 x^{2} : x = \frac{4}{5}, x = - 1

x = \frac{4}{5}, x = - 1

Verify Solutions:

x = \frac{4}{5}

True

, x = - 1

False

The solution is

x = \frac{4}{5}

ln (x) = x - 2

lo g_{3} (x + 1) = 2

\frac{lo g _{5} ( x ) - 4}{lo g _{5} ( x ) + 3} = 0

lo g_{2} (x^{2} - 4) + 1 = lo g_{2} (2 - x)

lo g_{4} (2^{x} + 48) = x - 1

What is the answer to log_{5}(4-x)-2log_{5}(x)=1 ?
The answer to log_{5}(4-x)-2log_{5}(x)=1 is x= 4/5
Solve for x: log_{5}(4-x)-2log_{5}(x)=1
The solution is x= 4/5