What is the answer to log_{2}(x)+log_{2}(x^2)+log_{3}(x^3)=6 ?

The answer to log_{2}(x)+log_{2}(x^2)+log_{3}(x^3)=6 is x=3^{(2log_{3}(2))/(1+log_{3)(2)}}

Solve for x: log_{2}(x)+log_{2}(x^2)+log_{3}(x^3)=6

The solution is x=3^{(2log_{3}(2))/(1+log_{3)(2)}}

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lo g_{2} (x) + lo g_{2} (x^{2}) + lo g_{3} (x^{3}) = 6

x = 3^{\frac{2 l o g _{3} ( 2 )}{1 + l o g _{3} ( 2 )}}

Decimal Notation

x = 2.33965 \dots

Solution steps

lo g_{2} (x) + lo g_{2} (x^{2}) + lo g_{3} (x^{3}) = 6

Apply log rules

x = 3^{\frac{2 l o g _{3} ( 2 )}{1 + l o g _{3} ( 2 )}}

Verify Solutions:

x = 3^{\frac{2 l o g _{3} ( 2 )}{1 + l o g _{3} ( 2 )}}

True

The solution is

x = 3^{\frac{2 l o g _{3} ( 2 )}{1 + l o g _{3} ( 2 )}}

lo g_{10} (x) (25) = lo g_{5} (x)

lo g_{2} (x) + lo g_{2} (x - 2) = 3

lo g_{3} (x^{2} - 2 x + 1) = lo g_{3} (x^{2} + x + 7)

x, ln (\frac{x}{y}) = 3

13 lo g_{10} (10 x) = 338 - x lo g_{10} (10)

What is the answer to log_{2}(x)+log_{2}(x^2)+log_{3}(x^3)=6 ?
The answer to log_{2}(x)+log_{2}(x^2)+log_{3}(x^3)=6 is x=3^{(2log_{3}(2))/(1+log_{3)(2)}}
Solve for x: log_{2}(x)+log_{2}(x^2)+log_{3}(x^3)=6
The solution is x=3^{(2log_{3}(2))/(1+log_{3)(2)}}