What is the answer to log_{10}(x)+log_{10}(x+2)=log_{10}(3x) ?

The answer to log_{10}(x)+log_{10}(x+2)=log_{10}(3x) is x=1

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log_{10}(x)+log_{10}(x+2)=log_{10}(3x)

lo g_{10} (x) + lo g_{10} (x + 2) = lo g_{10} (3 x)

x = 1

Solution steps

lo g_{10} (x) + lo g_{10} (x + 2) = lo g_{10} (3 x)

Apply log rules

x (x + 2) = 3 x

Solve

x (x + 2) = 3 x : x = 0, x = 1

x = 0, x = 1

Verify Solutions:

x = 0

False

, x = 1

True

The solution is

x = 1

lo g_{3} (1 + x) + lo g_{3} (x + 3) = 1

2 lo g_{10} (9 - 2 x) = (3 - x)

lo g_{10} (5 x + 1) = 2 + lo g_{10} (2 x - 3)

4 lo g_{2} (2 x) = 36

lo g_{10} (n) = - 0.35

What is the answer to log_{10}(x)+log_{10}(x+2)=log_{10}(3x) ?
The answer to log_{10}(x)+log_{10}(x+2)=log_{10}(3x) is x=1
Solve for x: log_{10}(x)+log_{10}(x+2)=log_{10}(3x)
The solution is x=1