What is the answer to log_{10}(n)=-0.35 ?

The answer to log_{10}(n)=-0.35 is n= 1/(10^{0.35)}

Solve for n: log_{10}(n)=-0.35

The solution is n= 1/(10^{0.35)}

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lo g_{10} (n) = - 0.35

n = \frac{1}{1 0 ^{0.35}}

Decimal Notation

n = 0.44668 \dots

Solution steps

lo g_{10} (n) = - 0.35

Apply log rules

n = \frac{1}{1 0 ^{0.35}}

lo g_{3} (x) + lo g_{3} (2 x + 1) = 1

lo g_{2} (x) = lo g_{4} (x^{2} + 2 x - 1)

lo g_{10} (10 x) - lo g_{10} (4 - x) = 2

lo g_{4} (y) + 2 = 3 \cdot lo g_{4} (4 y)

lo g_{2} (x^{2} - 4) - lo g_{2} (x - 2) = 3

What is the answer to log_{10}(n)=-0.35 ?
The answer to log_{10}(n)=-0.35 is n= 1/(10^{0.35)}
Solve for n: log_{10}(n)=-0.35
The solution is n= 1/(10^{0.35)}