What is the answer to log_{4}(y)+2=3*log_{4}(4y) ?

The answer to log_{4}(y)+2=3*log_{4}(4y) is y= 1/2

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log_{4}(y)+2=3*log_{4}(4y)

lo g_{4} (y) + 2 = 3 \cdot lo g_{4} (4 y)

y = \frac{1}{2}

Decimal

y = 0.5

Solution steps

lo g_{4} (y) + 2 = 3 lo g_{4} (4 y)

Apply log rules

y = \frac{1}{2}

Verify Solutions:

y = \frac{1}{2}

True

The solution is

y = \frac{1}{2}

lo g_{2} (x^{2} - 4) - lo g_{2} (x - 2) = 3

lo g_{3} (4 x^{3} + 14 x^{2} + 13 x + 3) = lo g_{3} (x + 1)

lo g_{10} (8 x) = \frac{7}{3}

ln (x + 5) - ln (x) = 3

lo g_{10} (n) = - 0.1302

What is the answer to log_{4}(y)+2=3*log_{4}(4y) ?
The answer to log_{4}(y)+2=3*log_{4}(4y) is y= 1/2
Solve for y: log_{4}(y)+2=3*log_{4}(4y)
The solution is y= 1/2